Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

ADD (uxtx, 64-bit)

Test 1: uops

Code:

  add x0, x0, x1, uxtx
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000
100410301001100110002560310001000200010011000

Test 2: Latency 1->2

Code:

  add x0, x0, x1, uxtx
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101082594161010710214202281000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024100301002110021100282595281003010038200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010

Test 3: Latency 1->3

Code:

  add x0, x1, x0, uxtx
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101072594351010710214202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024100301002110021100280259474010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200200201001110010
10024100301002110021100200259591010020100200201401002510010
10024100301002110021100200259591010020100200200201001110010

Test 4: throughput

Count: 8

Code:

  add x0, x8, x9, uxtx
  add x1, x8, x9, uxtx
  add x2, x8, x9, uxtx
  add x3, x8, x9, uxtx
  add x4, x8, x9, uxtx
  add x5, x8, x9, uxtx
  add x6, x8, x9, uxtx
  add x7, x8, x9, uxtx
  mov x8, 9
  mov x9, 10

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.3342

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
802042688880115801158012002403600801208022201602488001580100
802042676980115801158012002403600801208022401602488001580100
8020426737801158011580120614261239775981716815687151602488001580100
802042673780115801158012002403600801208022401602488001580100
802042673780115801158012002403600801208022401602488001580100
802042673780115801158012002403600801208022401602488001580100
802052677180157801578017102403600801208022401602488001580100
802042673780115801158012002403600801208022401602488001580100
802042673780115801158012002403600801208022401602488001580100
802042673780115801158012002403600801208022401602488001580100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.3339

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
800242802080039800398004426147780042800461600708002880010
800242677380021800218002028273880020800201600208001180010
800242671380021800218002027740480020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010
800242671380021800218002028273880020800201600208001180010