Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

ASR (immediate, 64-bit)

Test 1: uops

Code:

  asr x0, x0, #17
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100510601015101510402560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000

Test 2: Latency 1->2

Code:

  asr x0, x0, #17
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101082595391010710212102141000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072598391014910262102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072594351010710214102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100241003010021100210100302594741002010020100201001110010
100241003010021100210100202599441007010085100201001110010
12103253971191211187725112452599541007010080100361001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010
100241003010021100210100202595911002010020100201001110010

Test 3: throughput

Count: 8

Code:

  asr x0, x8, #17
  asr x1, x8, #17
  asr x2, x8, #17
  asr x3, x8, #17
  asr x4, x8, #17
  asr x5, x8, #17
  asr x6, x8, #17
  asr x7, x8, #17
  mov x8, 9

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.3342

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80204268908011580115801202403608012080224802228001580100
80204267498011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802208001480100
80205268808015880158801722403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802768005980100
80204267378011580115801202403608012080224802248001580100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.3339

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80024279448003880038800432561438004280046800208001180010
80024267848002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267428002180021800202774048002080020800208001180010
80024267148002180021800202774048002080020800208001180010