Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

CMP (register, lsl, 64-bit)

Test 1: uops

Code:

  cmp x0, x1, lsl #17
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 2.000

Integer unit issues: 2.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001
1004698200120011000146781000100020002001

Test 2: Latency 3->1

Chain cycles: 1

Code:

  cmp x0, x1, lsl #17
  cset x0, cc
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 1 chain cycle): 2.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
20204300303010130101201067893112010520210302153000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100
20204300303010130101201057893692010520212302183000110100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 1 chain cycle): 2.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
20024300303001130011200167893812001520030300203000110010
20024300303001130011200107899072004820062300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020301043001510010
20024300303001130011200107894382001020020300203000110010

Test 3: Latency 3->2

Chain cycles: 1

Code:

  cmp x0, x1, lsl #17
  cset x1, cc
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 1 chain cycle): 2.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
202043003030101301012010679115520257203823021500300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202043003030101301012010578936920105202123021800300010010100
202053006030115301152014078931120105202103021500300010010100
202043003030101301012010578936920105202123021800300010010100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 1 chain cycle): 2.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
20024300303001130011200157894592001520032300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20025300603002530025200517893602001020020300983001510010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010
20024300303001130011200107894382001020020300203000110010

Test 4: throughput

Count: 8

Code:

  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  cmp x0, x1, lsl #17
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.6675

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80204534041601171601178012711775938013080230160252160016100
80204534141601161601168012511776078012380224160248160014100
80204534021601141601148012311776318012380224160330160060100
80204534021601141601148012311776078012380224160248160014100
80204534021601141601148012311776278012380224160248160014100
80204534021601141601148012311776078012380224160248160014100
80204534021601141601148012311776158012380224160248160014100
80204534021601141601148012311776038012380224160248160014100
80204534021601141601148012311776318012380224160248160014100
80204534021601141601148012311776078012380224160248160014100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.6671

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
8002453383160040160040800490117224008004680046016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110
8002453371160021160021800200117003208002080020016002016001110