Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

FCVTAS (scalar, S to W)

Test 1: uops

Code:

  fcvtas w0, s0
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 2.000

Issues: 3.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 2.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch simd uop (57)ldst uops in schedulers (5b)dispatch uop (78)map simd uop (7e)map simd uop inputs (81)? int output thing (e9)? simd retires (ee)? int retires (ef)
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000
20041037300110012000200011000200020002000100110001000

Test 2: Latency 1->2 roundtrip

Code:

  fcvtas w0, s0
  fmov d0, x0
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 10.0032

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
3020410003240101101012000010000100200001000030015467862578206301002001000220004200100012000310001100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003200100012000310001100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003200100012000310001100001000010100
3020410003240101101012000010000100200001000030015468282578258301002001000120003200100202004010002100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003202100212004010003100001000010100
3020410003240101101012000010000100200001000030015468282578258301002001000120003200100012000310001100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003200100012000310001100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003200100012000310001100001000010100
3020410012040101101012000010000100200001000030015470902578674301002001000120003200100012000310001100001000010100
3020410003240101101012000010000100200001000030015467962578206301002001000120003200100012000310001100001000010100

1000 unrolls and 10 iterations

Result (median cycles for code): 10.0032

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
300241000344001110011200001000010200001000030154634625782063001020100012000320100022000410001100001000010010
300241000324001110011200001000010200001001630154672525788393005620100172003620100002000010001100001000010010
300241000324001110011200001000010200001000030154634625782063001020100002000020100002000010001100001000010010
300241000324001110011200001000010200001000030154634625782063001020100002000020100002000010001100001000010010
300241000324001110011200001000010200001001730154783125806073005720100172003620100002000010001100001000010010
300241000324001110011200001000010200001000030154634625782063001020100002000020100002000010001100001000010010
300241001264002010013200051000210200301001730154654625785273005720100192004120100002000010001100001000010010
300241000324001110011200001000010200001000030154634625782063001020100002000020100002000010001100001000010010
300241000324001110011200001000010200001000030154634625782063001020100002000020100002000010001100001000010010
300241000384001110011200001000010200001000030154681725789603001020100002000020100182003510003100001000010010

Test 3: throughput

Count: 8

Code:

  fcvtas w0, s8
  fcvtas w1, s8
  fcvtas w2, s8
  fcvtas w3, s8
  fcvtas w4, s8
  fcvtas w5, s8
  fcvtas w6, s8
  fcvtas w7, s8
  mov x8, 9

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map simd uop inputs (81)? int output thing (e9)? simd retires (ee)? int retires (ef)
1602048005724010380101160002100160008300880290160158200160068200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880290160158200160068200160012800018000080100
1602058007424015580115160040100160058300880053160110200160014200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100
1602048003724010380101160002100160008300880041160108200160012200160012800018000080100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
160024800402400138001116000201016000830880000160010201600002001600008000108000080010
160024801002400848003316005101016005430880000160010201600002001600008000108000080010
160024800372400118001116000001016000030880000160010201600002001600008000108000080010
11477876341169910580291104851396298111050230880338160072201600662001600128000108000080010
160024801082400848003316005101016005430880290160068201600682001600008000108000080010
160024800372400118001116000001016000030880000160010201600002001600008000108000080010
160024800372400118001116000001016000030880000160010201600002001600548002308000080010
160024800972400848003316005101016005430880000160010201600002001600008000108000080010
160024801012400848003316005101016005430880297160064201600542001600668001508000080010
160025800742400658002516004001016005830880594160118201601082001600008000108000080010