Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

FRINTX (scalar, S)

Test 1: uops

Code:

  frintx s0, s0
  movi v0.16b, 1
  movi v1.16b, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 1.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch simd uop (57)ldst uops in schedulers (5b)dispatch uop (78)map simd uop (7e)map simd uop inputs (81)? int output thing (e9)? simd retires (ee)
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000
1004303310011100010007590510001000100011000

Test 2: Latency 1->2

Code:

  frintx s0, s0
  movi v0.16b, 1
  movi v1.16b, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 3.0033

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
102043003310101101100001001000030076890510100200100062000100041010000100
102043003310101101100001001000030076890510100200100042000100051010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042020100442010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042000100041010000100
102043003310101101100001001000030076890510100200100042000100041010000100

1000 unrolls and 10 iterations

Result (median cycles for code): 3.0033

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map simd uop inputs (81)? int output thing (e9)? simd retires (ee)? int retires (ef)
10024300331002121100002010000707689051002020100062010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10025300661002721100062010031707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010
10024300331002121100002010000707689051002020100002010000111000010

Test 3: throughput

Count: 8

Code:

  frintx s0, s8
  frintx s1, s8
  frintx s2, s8
  frintx s3, s8
  frintx s4, s8
  frintx s5, s8
  frintx s6, s8
  frintx s7, s8
  movi v8.16b, 9

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5004

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
802044005080107101800061008001030032003680108200800122000800141080000100
802054008180145101800441008005630032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100
802044003580105101800041008000830032003680108200800122000800121080000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5004

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map simd uop (7e)map int uop inputs (7f)map simd uop inputs (81)? int output thing (e9)? simd retires (ee)? int retires (ef)
800244010580027218000602080010703200008002020800002080000118000010
800244003580021218000002080000703202168007620800682080000118000010
800244033080216218019502080195703200008002020800002080195118000010
800244003580021218000002080000703200008002020800002080000118000010
800244003580021218000002080000703200008002020800002080000118000010
800244003580021218000002080000703200008002020800002080000118000010
800244003580021218000002080000703200008002020800002080000118000010
800244003580021218000002080000703200008002020800002080000118000010
800244003580021218000002080000703200008002020800002080048118000010
800244008480021218000002080000703200008002020800002080000118000010