Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LD1 (multiple, post-index, 2 regs, 2D)

Test 1: uops

Code:

  ld1 { v0.2d, v1.2d }, [x6], x8
  nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop
  mov x0, 1
  mov x1, 2
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires (minus 60 nops): 2.000

Issues: 3.000

Integer unit issues: 1.001

Load/store unit issues: 2.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
6200529823300710032004100220003000600030002000300010012000
6200429623300110012000100020003000600030002000300010012000
6200429653300110012000100020003000600030002000300010012000
6200429622300110012000100020003000600030002000300010012000
6200429611300110012000100020003000600030002000300010012000
6200429615300110012000100020003000600030002000300010012000
6200429616300110012000100020003000600030002000300010012000
6200429652300110012000100020003000600030002000300010012000
6200429622300110012000100020003000600030002000300010012000
6200429620300110012000100020003000600030002000300010012000

Test 2: Latency 1->3 roundtrip

Chain cycles: 3

Code:

  ld1 { v0.2d, v1.2d }, [x6], x8
  fmov x0, d0
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60205100153801105010210006200024013210012200062659433156760078892070113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60205100082801155010910004200024013610013200062659282156758878889770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602783004210013500092000040100
60204100060801035010110002200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100
60204100042801025010110001200004010410003200062659343156769278893770113302092000810003602183001210003500012000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60025100145800205001210006200024004210012200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60025100181800255001910004200024004610013200002659789156952478981370010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600983004210013500092000040010

Test 3: Latency 2->3 roundtrip

Chain cycles: 3

Code:

  ld1 { v0.2d, v1.2d }, [x6], x8
  fmov x1, d1
  eor x8, x8, x1
  eor x8, x8, x1
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60205100155801105010210006200024013210012200062659383156756678890170113302092000810003602183001210003500012000040100
60204100047801035010110002200004010410003200062659478156777278898270113302092000810003602783004210013500092000040100
60204100047801035010110002200004010410003200062659478156777278898270113302092000810003602183001210003500012000040100
60204100081801035010110002200004010410003200242659946156803478911670173302392002810013602183001210003500012000040100
60205100080801155010910004200024013610013200062659559156782678900970113302092000810003602183001210003500012000040100
60204100047801035010110002200004010410003200062659478156777278898270113302092000810003602183001210003500012000040100
60205100080801155010910004200024013610013200062659910156806078911470113302092000810003602183001210003500012000040100
60204100047801035010110002200004010410003200242660698156852678935970173302392002810013602183001210003500012000040100
60204100047801035010110002200004010410003200242660158156815478918870173302392002810013602183001210003500012000040100
60205100080801155010910004200024013610013200062659478156777278898270113302092000810003602763003910013500092000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60025100153800205001210006200024004210012200062659519156932478972470023300292000810003600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60025100080800255001910004200024004610013200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600983004210013500092000040010
60024100047800135001110002200004001010000200002659546156936278973570010300202000010000600203000010000500012000040010

Test 4: throughput

Count: 8

Code:

  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  ld1 { v0.2d, v1.2d }, [x6], x8
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
16020580149240161801311600308013216001035798950419424011720016001420024002180005160000100
160204800532401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100
160204800452401058010516000080106160008280397128393624011420016001220024001880005160000100
160204800452401058010516000080106160008280392128001224011420016001220024001880005160000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
16002580189240077800411600368004316001032007688024824002720160014202400008000116000010
160025801082400748004016003480042160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024801022400118001116000080010160192307886101297824030620160224202400008000116000010
160024800622400118001116000080010160000280051128023224001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
16002480054240011800111600008001016019232681082401424030620160224202404208013116000010
16002480744240291801411601508014016024034935260143824038020160280202404208013116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010