Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LD1 (multiple, post-index, 2 regs, 8H)

Test 1: uops

Code:

  ld1 { v0.8h, v1.8h }, [x6], x8
  nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop
  mov x0, 1
  mov x1, 2
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires (minus 60 nops): 2.000

Issues: 3.000

Integer unit issues: 1.001

Load/store unit issues: 2.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
6200529771300710032004100220003000600030002000300010012000
6200429386300110012000100020003000600030002000300010012000
6200429338300110012000100020003000600030002000300010012000
6200429339300110012000100020003000600030002000300010012000
6200429338300110012000100020003000600030002000300010012000
6200429338300110012000100020003000600030002000300010012000
6200429361300110012000100020003000600030002000300010012000
6200429359300110012000100020003000600030002000300010012000
6200429338300110012000100020003000600030002000300010012000
6200429343300110012000100020003000600030002000300010012000

Test 2: Latency 1->3 roundtrip

Chain cycles: 3

Code:

  ld1 { v0.8h, v1.8h }, [x6], x8
  fmov x0, d0
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60205100149801105010210006200024013210012200062659486156200879149370113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062663096157018079013970113302092000810003602183001210003500012000040100
60204100054801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60205100082801155010910004200024013610013200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60025100151800205001210006200024004210012200002659542156928278970970010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002660842157023679013770010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100044800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60025100075800245001910003200024004610013200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010

Test 3: Latency 2->3 roundtrip

Chain cycles: 3

Code:

  ld1 { v0.8h, v1.8h }, [x6], x8
  fmov x1, d1
  eor x8, x8, x1
  eor x8, x8, x1
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60205100149801105010210006200024013210012200062659421156758878891570113302092000810003602183001210003500012000040100
60205100082801155010910004200024013610012200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60205100138801155010910004200024013610013200062659613156785878902770113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100
60204100049801035010110002200004010410003200062659532156780478900070113302092000810003602183001210003500012000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
60025100155800205001210006200024004210012200062659433156935078972170023300292000810003600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600983004210013500092000040010
60024100044800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010
60024100042800125001110001200004001010000200242662678157144879072070083300592002810013600203000010000500012000040010
60024100042800125001110001200004001010000200002659411156928278969070010300202000010000600203000010000500012000040010

Test 4: throughput

Count: 8

Code:

  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  ld1 { v0.8h, v1.8h }, [x6], x8
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
16020580175240164801301600348013216001035799150419424011720016001420024002180005160000100
16020480059240105801051600008010616001035798950188224011720016001420024002180005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160205801082401648013016003480132160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100
160204800562401058010516000080106160008280386128024824011420016001220024001880005160000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
16002580181240074800401600348004216000033604872021824001020160000202400008000116000010
160025801112400718004116003080042160058286820121635024010020160072202401028003016000010
160024801522400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010
160024800542400118001116000080010160058293201115052424010020160072202400008000116000010
160024800542400118001116000080010160000280051128021824001020160000202400008000116000010