Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDP (signed offset, D)

Test 1: uops

Code:

  ldp d0, d1, [x6, #0x10]
  mov x0, 1
  mov x1, 2
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 2.000

Issues: 2.000

Integer unit issues: 0.001

Load/store unit issues: 2.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
117567585610717490728578247273020001616420002000200012000
2004105120011020000020001616420002000200012000
2004105120011020000020001616420002000200012000
2004105120011020000020001836020002000200012000
2004105420011020000020001629020002000200012000
2004105420011020000020001621820002000200012000
2004105420011020000020001621820002000200012000
2004105620011020000020001627220002000200012000
2004105420011020000020001627220002000200012000
2004105820011020000020001621820002000200012000

Test 2: Latency 1->3 roundtrip

Chain cycles: 3

Code:

  ldp d0, d1, [x6, #0x10]
  fmov x0, d0
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
602051001497010940101100062000230130100152000426692531779454109314260110302112000810004602242000810004400012000040100
602041000517010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602222000810004400012000040100
602041000497010340101100022000030103100032000426692261779436109313160110302112000810004602882002810015400082000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
6002510015670019400111000620002300401001520004266921717793261049469600203003220008100046004420008100044000120000040010
6002410004770013400111000220000300131000320004266908017792741049460600203003220008100046004420008100044000120000040010
6002410004070012400111000120000300131000320004266908017792741049460600203003220008100046004420008100044000120000040010
6002410004070012400111000120000300131000320004266908017792741049460600203003220008100046004420008100044000120000040010
6002410004070012400111000120000300101000020000266906017792301049412600103002020000100006002020000100004000120000040010
6002410004070012400111000120000300101000020000266906017792301049412600103002020000100006002020000100004000120000040010
6002410004070012400111000120000300101000020000266906017792301049412600103002020000100006002020000100004000120000040010
6002410004070012400111000120000300101000020000266906017792301049412600103002020000100006002020000100004000120000040010
6002410004070012400111000120000300101000020024266943717795021049562600823006520028100156002020000100004000120000040010
6002410004070012400111000120000300101000020000266906017792301049412600103002020000100006002020000100004000120000040010

Test 3: Latency 2->3 roundtrip

Chain cycles: 3

Code:

  ldp d0, d1, [x6, #0x10]
  fmov x1, d1
  eor x8, x8, x1
  eor x8, x8, x1
  add x6, x6, x8
  mov x0, 1
  mov x1, 2
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
602051001567010940101100062000230130100152000426691411779300104844360110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602862002810015400082000040100
602041000557010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000517010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100
602041000497010340101100022000030103100032000426692331779436104857060110302122000810004602242000810004400012000040100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 7.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? int retires (ef)
600251001537001940011100062000230040100152000026692491779356104948960010300202000010000600202000010000400012000040010
600241000477001340011100022000030010100002000026692491779356104948960010300202000010000600202000010000400012000040010
600241000477001340011100022000030010100002000026692491779356104948960010300202000010000600202000010000400012000040010
600241000477001340011100022000030010100002000026692491779356104948960010300202000010000600442000810004400012000040010
600241002477004540029100082000830074100222000026693031779392104951160010300202000010000601482004010022400192000040010
600241008087004440028100082000830075100222000026694111779464104955560010300202000010000601522004010022400192000040010
600241000497001340011100022000030010100002000026692761779374104950060010300202000010000611042034110186401512000040010
600241027627033440192100622008030653102202000026692491779356104948960010300202000010000600202000010000400012000040010
600241000477001340011100022000030010100002002426713001780744105031860082300652002810015600202000010000400012000040010
600241000477001340011100022000030010100002000026692491779356104948960010300202000010000600202000010000400012000040010

Test 4: throughput

Count: 8

Code:

  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  ldp d0, d1, [x6, #0x10]
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
160205801641601311011600301001600563004965121601562001600682001600121160000100
1602048006716010510116000410016000830012801941601082001600122001600121160000100
1602048014116010110116000010016010630711908741602082021601282001600121160000100
1602048049316022110116012010016000830012801941601082001600122001600121160000100
1602048005316010110116000010016000830012801941601082001600122001600121160000100
1602048005316010110116000010016000830012801941601082001600122001600121160000100
1602048005316010110116000010016000830012801941601082001600122001600121160000100
160204800531601011011600001001600563006944021601562001600682001600121160000100
1602048005316010110116000010016000830012801941601082001600122001600121160000100
160204800531601011011600001001600563007496721601562001600682001600121160000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
1600258019116004511160034101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012805061600102016000020160000116000010
1600248005416001111160000101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012803801600102016000020160068116000010
1600258011116004511160034101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012802181600102016000020160000116000010
1600248005416001111160000101600003012803621600102016000020160000116000010
1600248005916001111160000101600003012802181600102016000020160000116000010