Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRB (register)

Test 1: uops

Code:

  ldrb w0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056611027110261000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrb w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
40205701564010830107100013013010003185934469385140106302101000460220200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100
40204700404010230102100003010310003185939269399340106302121000460224200083000210000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570265400183001710001300401000018597606947564001030020100006002020000300031000030010
4002470058400133001310000300101000018598146947784001030020100006002020000300031000030010
4002470059400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470052400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470050400133001310000300101000018597336947454001030020100006002020000300031000030010
4002470051400133001310000300101000018597606947564001030020100006012220034300091000030010
4002470051400133001310000300101000018597876947674001030020100006002020000300031000030010
4002470052400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470053400133001310000300101000018597606947554001030020100006002020000300031000030010
4002470052400133001310000300101000018598416947894001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrb w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570153401083010710001301301000318595396938964010630210100046022020008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020570138401103010810002301351000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
40025701594001830017100013004010003185967769371640016300301000460020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024701734001330013100003001010000185997669484340010300201000060020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024700494001330013100003001010000185976069475640010300201000060122200343000910000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010
40024700494001330013100003001010000185970669473440010300201000060020200003000310000030010

Test 4: throughput

Count: 8

Code:

  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  ldrb w0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401908013110180030100800083002801908010820080012200160028180000100
80204400468010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80205400988013810180037100800103005683628011020080014200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402838004311800321080010306402088002020800142016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024401668001111800001080000306405628001020800002016000018000010
80024400668001111800001080000306403468001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010