Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRH (register)

Test 1: uops

Code:

  ldrh w0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056551027110261000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000825610001000200011000
10045541001110001000845410001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570513401083010710001301301000318595396938964010630210100046022020008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020570086401103010810002301351000318599326942084010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570153400183001710001300401000018596586936744001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002570079400213001910002300421000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570146401083010710001301301000318594856938764010630210100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318597976941514010630212100046022420008300031000030100
4020470047401033010310000301031000318602566943384010630212100046022420008300031000030100
4020470068401043010410000301031002718639976958024019430286100306022020008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570169400183001710001300401000318594346936264001630030100046002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006011620034300091000030010
4002470065400123001210000300101000018597066947434001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  ldrh w0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401948013110180030100800083003282628010820080012200160024180000100
80204400578010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402288004511800341080008304001368001820800122016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400548001111800001080057306173578006720800702016000018000010
80024400698001111800001080000306403108001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010