Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRH (register, lsl)

Test 1: uops

Code:

  ldrh w0, [x6, x7, lsl #1]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056831029110281000823810001000200011000
10045541001110001000811210001000200011000
10045471001110001000771510001000200011000
10045431001110001000807610001000200011000
10045431001110001000816610001000200011000
10045431001110001000804010001000200011000
10045541001110001000811210001000200011000
10045761001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570150401083010710001301301000318595396938964010630210100046022020008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031001518601407251614015030248100176022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570165400183001710001300401000318596236936964001630030100046002020000300031000030010
4002470047400133001310000300101001518599877056344006030068100176002020000300031000030010
4002570077400213001910002300451000018608737301384001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101001518600166948554006030071100176002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570153401083010710001301301000318595336939214010630210100046022020008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020570077401113010910002301351000318601756943054010630212100046022420008300031000030100
4020470049401033010310000301031000318596896941034010630212100046022420008300031000030100
4020470049401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0043

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
400257016240018300171000130040100031859677693718040016300301000406035020114300391000030010
400247007140013300131000030013100031859671694738040016300321000406002020000300031000030010
400247007440014300141000030013100001859658693674040010300201000006002020000300031000030010
400247004940013300131000030010100001859706694734040010300201000006002020000300031000030010
400247004940013300131000030010100001859706694734040010300201000006002020000300031000030010
400247004940013300131000030010100001859706694734040010300201000006002020000300031000030010
400247004940013300131000030010100151860070694875040060300711001706002020000300031000030010
400247004940013300131000030010100001859706694734040010300201000006002020000300031000030010
400247004940013300131000030010100001859706694734040010300201000006002020000300031000030010
400247005340013300131000030010100521866775697495040194301761005206002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  ldrh w0, [x6, x7, lsl #1]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401918013310180032100800083003282628010820080012200160028180000100
80204400578010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
8002540247800331180022108000830400190080018208001202016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440136800111180000108000030640472080010208000002016000018000010
8002440063800111180000108000030640166080010208000002016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440050800111180000108000030640166080010208000002016000018000010
8002440050800111180000108005830410426080068208007102016000018000010