Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRH (register, sxtw)

Test 1: uops

Code:

  ldrh w0, [x6, w7, sxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056801023110221000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045541001110001000816610001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570168401083010710001301301000318595816940634010630212100046022020008300031000030100
4020570163401123011010002301351000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318596626940964010630212100046022420008300031000030100
4020470048401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318619846950424010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470058401033010310000301031000318597976941514010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002670549400263002310003300721000318599476938284001630030100046009820026300121000030010
4002470061400123001210000300101000018596526947144001030020100006002020000300031000030010
4002470040400123001210000300101000018605166950664001030020100006002020000300031000030010
4002470040400123001210000300101000018597336947474001030020100006002020000300031000030010
4002470422400603004810012301421000018596526947144001030020100006012220034300111000030010
4002470043400123001210000300101000418614267303764001730032100056002020000300031000030010
4002470040400123001210000300101000018596526947144001030020100006002020000300031000030010
4002470044400123001210000300101000018604086950224001030020100006032820104300391000030010
4002470040400123001210000300101000018596526947144001030020100006002020000300031000030010
4002470040400123001210000300101000018596526947144001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrh w0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570150401083010710001301301000318593506938264010630210100046022020008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046030220034300081000030100
4020470048401023010210000301031000318595816940684010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318596086940784010630212100046022420008300021000030100
4020570072401103010810002301351000318599056941994010630212100046022420008300031000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570156400183001710001300401000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470053400133001310000300101000418596717296534001730032100056002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  ldrh w0, [x6, w7, sxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
8020540296801371010800361000800083002482628010820080012200160028180000100
8020440050801011010800001000800083006402508010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100
8020440049801011010800001000800083006401428010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402718004111800301080008303202628001820800122016000018000010
80024400548001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080057303428918006720800692016000018000010
80024400508001111800001080000306402208001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400538001111800001080000306402748001020800002016000018000010
80024400668001111800001080000306402208001020800002016000018000010