Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSB (register, 32-bit)

Test 1: uops

Code:

  ldrsb w0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056861027110261000823810001000200011000
10045541001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000300010001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsb w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318593506938264010630210100046022420008300021000030100
4020470042401023010210000301031001518597916941304015030251100176022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046029420034300081000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470043401023010210000301031000318594466940134010630212100046029620034300081000030100
4020470074401043010410000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470045401023010210000301031000318594736940234010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570156400183001710001300401000318594346936264001630030100046011820034300081000030010
4002470047400133001310000300131000018594636946444001030020100006002020000300021000030010
4002470042400123001210000300101000018616506955354001030020100006002020000300021000030010
4002470043400123001210000300101000018594906946554001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101001518598276947854006030071100176002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsb w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318595396938964010630210100046022020008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570086401123011010002301351000318596356940834010630212100046022420008300031000030100
4020470051401033010310000301031000318610936946234010630212100046022020008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570522400183001710001300401000318597256947584001630032100046002020000300031000030010
4002570079400213001910002300451000018601716938904001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470045400123001210000300101005218657226970524019430172100526002020000300021000030010
4002470053400123001210000300101002618627146959074010230098100266002020000300021000030010
4002470224400363003010006300761000018595176946644001030020100006002020000300021000030010
4002470136400243002110003300431001318611566944894005630057100136002020000300021000030010
4002470135400243002110003300431000018595176946644001030020100006002020000300021000030010
4002470218400363003010006300761000018595176946644001030020100006020020060300171000030010
4002470940401083008410024302741014418811797186744051830439101446093420320301101000030010

Test 4: throughput

Count: 8

Code:

  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  ldrsb w0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205403218013510180034100800083002561908010820080012200160028180000100
80204400538010110180000100800103002442688011020080014200160024180000100
80204400558010510180004100800083006401428010820080012200160024180000100
80204400498010110180000100800083006403048010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800103006401548011020080014200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)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