Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSB (register, 64-bit)

Test 1: uops

Code:

  ldrsb x0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056761027110261000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsb x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570149401083010710001301301000318595396938964010630210100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596896941054010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570079401113010910002301351000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570166400183001710001300401000018597606947544001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470108400133001310000300101001518608536951944006030071100176002020000300021000030010
4002470049400133001310000300101000018598416947894001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsb x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570147401083010710001301301000318594856938764010630210100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020570077401113010910002301351000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570153400183001710001300401000018595176946644001030020100006002020000300031000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470105400123001210000300101000018598416947964001030020100006002020000300021000030010
4002470047400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  ldrsb x0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401768013510180034100800083002481908010820080012200160024180000100
80204400638010110180000100800083006404308010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800593003293598015920080072200160024180000100
80204400528010110180000100800103006402088011020080014200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402198004511800341080008304002628001820800122016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80025401108004811800371080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010