Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, 32-bit)

Test 1: uops

Code:

  ldrsh w0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056761021110201000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000
10045501001110001000816610001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570153401083010710001301301000318594376938314010630210100046022420008300031000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031001518597376940744015030247100176022020008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
40025701554001830017100013004010003185967769371640016300301000460040200083000310000030010
40024700494001330013100003001010000185951769466440010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010
40024700424001230012100003001010000186124569536840010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010
40024700474001230012100003001010000185986869480740010300201000060020200003000210000030010
40024700424001230012100003001010000185951769466440010300201000060020200003000210000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh w0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020670176401173011410003301641000318603106943674010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570146400183001710001300401000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018594906946554001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006011420034300081000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002570157400213001910002300451000018596796947324001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  ldrsh w0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401868013510180034100800083002428868010820080012200160028180000100
80204400578010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800573005943248015720080069200160024180000100
80204400628010110180000100800083006402688010820080012200160024180000100
80204402678010110180000100800103006402808011020080014200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025403048003511800241080000303201668001020800002016000018000010
80024400508001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306403108001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080048306340538005820800572016000018000010
80024400438001111800001080000306400768001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010