Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, 64-bit)

Test 1: uops

Code:

  ldrsh x0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10057891029110281000823810001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570156401083010710001301301000318595396938964010630210100046029420034300091000030100
4020470049401033010310000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020570072401103010810002301351000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570158400183001710001300401000318596716947384001630032100046002020000300031000030010
4002470047400133001310000300101000018602466949564001030020100006002020000300031000030010
4002470047400133001310000300101000018598416947874001030020100006002020000300031000030010
4002470050400133001310000300131000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018617316955594001030020100006002020000300031000030010
4002470057400133001310000300101000018597336947454001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570150401083010710001301301002718622107180794019430287100306022020008300031000030100
4020470050401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570173401113010910002301351000318598246941604010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570209400183001710001300401000318597796947804001630032100046002020000300031000030010
4002470049400133001310000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101001618598526981334006130071100186002020000300021000030010
4002470043400123001210000300101000418596717296534001730032100056002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  ldrsh x0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80206402238016410180063100800083002727788010820080012200160028180000100
80204400628010110180000100800083006403768010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160024180000100
80204400568010110180000100800083006402688010820080012200160138180000100
80204401638010110180000100800083006405028010820080012200160144180000100
80204401508010110180000100801349226450288033339480152200160024180000100
80204400638010110180000100800083006405208010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)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