Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, lsl, 32-bit)

Test 1: uops

Code:

  ldrsh w0, [x6, x7, lsl #1]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056631025110241000823810001000200011000
10045541001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh w0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318595396938964010630210100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470147401033010310000301031000418599057287094010730212100056022420008300031000030100
4020470052401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318597706941384010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570156400183001710001300401000018596586936744001030020100006002020000300031000030010
4002470049400133001310000300101001618600346948824006330071100186002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101001618600417135294006130071100186002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh w0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570149401083010710001301301000418595757285734010730212100056022020008300031000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031001618630027238394015330251100186022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300031000030100
4020470048401023010210000301031000318595816940704010630212100046029420034300081000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470043401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570525400183001710001300401000018596586936744001030020100006002020000300031000030010
4002470049400133001310000300101000018595716946864001030020100006002020000300021000030010
4002470048400123001210000300101001518598816948054006030071100176002020000300031000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006012220034300091000030010

Test 4: throughput

Count: 8

Code:

  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  ldrsh w0, [x6, x7, lsl #1]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401688012710180026100800083002481908010820080012200160024180000100
80204400538010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160144180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402258003911800281080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400658001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010
80024400548001111800001080000306402388001020800002016000018000010