Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, lsl, 64-bit)

Test 1: uops

Code:

  ldrsh x0, [x6, x7, lsl #1]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056591029110281000823810001000200011000
10045471001110001000823810001000200011000
10045541001110001000823810001000200011000
10045651001110001000827410001000200011000
10045541001110001000829210001000200011000
10045471001110001000813010001000200011000
10045551001110001000811210001000200011000
10045541001110001000823810001000200011000
10045541001110001000811210001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570486401083010710001301301000318592966938064010630210100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046030220034300081000030100
4020470068401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470066401023010210000301031000318598516941804010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570159400183001710001300401000018596586936744001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470063400133001310000300101001518620417058114006030068100176002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101002718632236951394010430108100306002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470056400133001310000300101000018597336947454001030020100006002020000300031000030010
4002570173400213001910002300451000018597876947674001030020100006004420010300031000030010
4002470047400133001310000300131001518619876956484006030071100176002020000300031000030010
4002570091400213001910002300451000018598686948024001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, x7, lsl #1]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570153401083010710001301301000318594916937364010630210100046022420008300031000030100
4020570079401113010910002301351000318602566943364010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031001518598816941914015230251100176022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570161400183001710001300401001218599806937814005430059100136002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470072400133001310000300101000018597336947454001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597876947674001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002570079400213001910002300451000018597606947564001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  ldrsh x0, [x6, x7, lsl #1]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205403688013710180036100800083002482628010820080012200160024180000100
80204400578010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80204400498010110180000100800083006402688010820080012200160024180000100
80205401068013110180030100800573006417158015720080069200160028180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
8002540251800371180026108000830320190080018208001202016000018000010
8002440050800111180000108000030640040080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016013818000010
8002440043800111180000108000030640040080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016013818000010
8002440124800111180000108000030640130080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016000018000010
8002440043800111180000108000030640040080010208000002016000018000010