Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, sxtw, 64-bit)

Test 1: uops

Code:

  ldrsh x0, [x6, w7, sxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056651025110241000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570155401083010710001301301000318595186938874010630210100046022420008300021000030100
4020470042401023010210000301031000318593986938714010630210100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020570084401103010810002301351000318596086940794010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570162400183001710001300401000318595636946994001630032100046004420008300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470046400123001210000300101005218660716971914019430172100526002020000300021000030010
4002470131400243002110003300431011918721777026474042830378101216002020000300021000030010
4002470230400363003010006300761005318693657015934019530170100536002020000300011000030010
4002470050400123001210000300101000018598416947964001030020100006002020000300021000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570168401083010710001301301000318595936939184010630210100046022020008300031000030100
4020470049401033010310000301031001518599806941394015030247100176022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570086401123011010002301351000318602296943254010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570253400183001710001300401001518600226947204006030069100176004020008300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010
4002470045400123001210000300101000018597066947344001030020100006002020000300031000030010
4002570072400203001810002300451000018597066947344001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  ldrsh x0, [x6, w7, sxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401628013510180034100800083002481368010820080012200160028180000100
80204400508010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160138180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006404488010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006402508010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402798004111800301080008302798688001820800122016000018000010
80024400518001111800001080000306401128001020800002016000018000010
80025401038004811800371080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400478001111800001080000306401128001020800002016000018000010
80024400568001111800001080000306407788001020800002016000018000010
80024400558001111800001080000306403288001020800002016000018000010