Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSH (register, uxtw, 64-bit)

Test 1: uops

Code:

  ldrsh x0, [x6, w7, uxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056861027110261000816610001000200011000
10045501001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, w7, uxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570517401083010710001301301000318602686941934010630210100046022020008300031000030100
4020470056401033010310000301031000318597976941474010630212100046022420008300031000030100
4020470052401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570160400183001710001300401001518602596949454006030071100176004020008300031000030010
4002470053400133001310000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101001518600706943334006030067100176002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsh x0, [x6, w7, uxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570151401083010710001301301000318595396938964010630210100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470136401033010310000301031000318602296943254010630212100046022420008300031000030100
4020470054401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570079401113010910002301351000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570162400183001710001300401000018596046936544001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006012220034300101000030010
4002470050400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  ldrsh x0, [x6, w7, uxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401838013110180030100800083003033688010820080012200160028180000100
80204400778010510180004100800083006401428010820080012200160138180000100
80204400638010110180000100808073003358730281923162180946200160028180000100
80204400558010110180000100800083006403048010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80026407118006911800581080008303545548001820800122016000018000010
80024400468001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010