Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDRSW (register)

Test 1: uops

Code:

  ldrsw x0, [x6, x7]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056741027110261000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000
10045471001110001000811210001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldrsw x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570288401083010710001301301000318596356940834010630212100046022420008300021000030100
4020470042401023010210000301031000318593986938714010630210100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020570170401103010810002301351000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100
4020470042401023010210000301031000318594466940134010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570155400183001710001300401000318596776937164001630030100046002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101001518600706939394006030067100176002020000300031000030010
4002470051400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470054400133001310000300101000018597606947564001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldrsw x0, [x6, x7]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570150401083010710001301301000318595396938964010630210100046029820034300091000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046030020036300111000030100
4020470054401033010310000301031000318597976941494010630212100046022420008300031000030100
4020470057401033010310000301031001518602506943104015030251100176022420008300031000030100
4020470049401033010310000301031001518599806942004015030251100176022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570154400183001710001300401000318595756936334001630032100046002020000300031000030010
4002470047400133001310000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  ldrsw x0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80206403118016810180067100800083004182648010820080012200160024180000100
80204400598010510180004100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400488010110180000100800083006410068010820080012202160480280000100
80204400828010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006401608010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
8002540336800391108002810080000302607568001020800002016000018000010
8002440050800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010
8002440043800111108000010080000306400408001020800002016000018000010