Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDR (register, lsl, 32-bit)

Test 1: uops

Code:

  ldr w0, [x6, x7, lsl #2]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056661027110261000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000829210001000200011000
10045541001110001000829210001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, x7, lsl #2]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570147401083010710001301301000318595876939434010630210100046022420008300031000030100
4020470047401033010310000301031001518617356949244015030251100176022420010300031000030100
4020470047401033010310000301031000318595816940634010630212100046022020008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046030220036300091000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570197400183001710001300401000018597336947444001030020100006002020000300021000030010
4002470417400603004810012301421000018599496948404001030020100006002020000300031000030010
4002470053400123001210000300101000018597066947414001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018598146947844001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002570095400213001910002300421000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, x7, lsl #2]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570145401083010710001301301000318595936939204010630210100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020570077401113010910002301351000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
400257017040018300171000130040100001860279693904400103002010000600202000003000410000030010
400247007240014300141000030010100001859706694734400103002010000600202000003000310000030010
400247004940013300131000030010100001861614695506400103002010000600202000003000310000030010
400247005740013300131000030010100001859733694744400103002010000600202000003000310000030010
400257007940021300191000230045100001859976694844400103002010000600202000003000310000030010
400257008140021300191000230045100001859706694734400103002010000600202000003000310000030010
400247005140013300131000030010100001859706694734400103002010000600202000003000310000030010
400247004940013300131000030010100001859706694734400103002010000600202000003000310000030010
400247004940013300131000030010100001859706694734400103002010000600202000003000310000030010
400247004940013300131000030010100001859706694734400103002010000600202000003000310000030010

Test 4: throughput

Count: 8

Code:

  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  ldr w0, [x6, x7, lsl #2]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401728012910180028100800083002561008010820080012200160024180000100
80204400488010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400478010110180000100800083006401068010820080012200160024180000100
80204400528010110180000100800083006402148010820080012200160024180000100
80204400478010110180000100800083006401608010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402358003911800281080008304002988001820800122016002818000010
80024400568001111800001080000306402748001020800002016000018000010
80024400628001111800001080010305432068002020800142016000018000010
80024400558001111800001080000306402028001020800002016000018000010
80024400588001111800001080000306404368001020800002016000018000010
80024400578001111800001080000306402028001020800002016000018000010
80024400528001111800001080000306402028001020800002016000018000010
80024400528001111800001080000306402028001020800002016000018000010
80024400528001111800001080000306402028001020800002016000018000010
80024400528001111800001080000306402028001020800002016000018000010