Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDR (register, sxtw, 32-bit)

Test 1: uops

Code:

  ldr w0, [x6, w7, sxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
100511581031110301000816610001000200011000
10045501001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318595336939214010630210100046022420008300031000030100
4020470047401033010310000301031000318595336939214010630210100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020570077401113010910002301351000318600136942394010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470122401033010310000301031000318598516941734010630212100046052820112300401000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570290400183001710001300401000318598936938064001630030100046002020000300031000030010
4002470051400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018597336947444001030020100006002020000300031000030010
4002470048400133001310000300101000018596796947254001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010
4002470047400133001310000300101000018596526947144001030020100006011620034300091000030010
4002470047400133001310000300101000018596526947144001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570156401083010710001301301000318595666939094010630210100046022020008300041000030100
4020470104401043010410000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020670189401223011810004301691000318597766940184010630210100046022420008300031000030100
4020470047401033010310000301031001518607366945104015030251100176022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031000318595816940634010630212100046022420008300031000030100
4020470047401033010310000301031001518599266941804015030251100176022420008300041000030100
4020470072401043010410000301031000318595396938964010630210100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570160400183001710001300401000318596236936964001630030100046002020000300031000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101001518598276940674006030067100176002020000300021000030010
4002470044400123001210000300101001518607186943594006030067100176002020000300021000030010
4002470041400123001210000300101000018595716946844001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  ldr w0, [x6, w7, sxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401588012910180028100800083002481368010820080012200160028180000100
80204400508010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800563004138868015620080069200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100
80204400498010110180000100800083006401428010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5009

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025403218004311800321080000303202388001020800002016000018000010
80025401108004211800311080000303523208001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010
80024400758001111800001080000306406168001020800002016000018000010