Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDR (register, sxtw, 64-bit)

Test 1: uops

Code:

  ldr x0, [x6, w7, sxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056561027110261000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000
10045541001110001000823810001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldr x0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318595396938964010630210100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022020008300031000030100
4020470133401033010310000301031000318599326942044010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020570079401113010910002301351000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0040

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570525400183001710001300401000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101001518598276944414006030067100176002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470040400123001210000300101000018594636946444001030020100006002020000300021000030010
4002470044400123001210000300101001518598816943584006030067100176002020000300021000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldr x0, [x6, w7, sxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570291401083010710001301301000318595876939414010630210100046022020008300031000030100
4020470091401033010310000301031000318603106943584010630212100046022020008300031000030100
4020470060401023010210000301031000318596356940834010630212100046022420008300031000030100
4020570072401103010810002301351000318596356940834010630212100046022420008300031000030100
4020470042401023010210000301031000318596626940944010630212100046022420008300031000030100
4020470042401023010210000301031000318596356940834010630212100046022420008300031000030100
4020470042401023010210000301031000318596356940834010630212100046022420008300031000030100
4020470042401023010210000301031000318596356940834010630212100046022420008300031000030100
4020470042401023010210000301031000318596356940834010630212100046022420008300031000030100
4020470042401023010210000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570153400183001710001300401000018599226948214001030020100006002020000300021000030010
4002470049400133001310000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101001518598816948054006030071100176002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010

Test 4: throughput

Count: 8

Code:

  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  ldr x0, [x6, w7, sxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5007

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205401838013110180030100800083002561908010820080012200160028180000100
80204400708010110180000100800083006405208010820080012200160024180000100
80204400588010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160142180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100
80204400708010110180000100800083006401968010820080012200160024180000100
80204400528010110180000100800083006401968010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025403698004111800301080000306401128001020800002016000018000010
80024400568001111800001080000306402208001020800002016025418000010
80024401468001111800001080010302543548002020800142016000018000010
80024400588001111800001080000306400408001020800002016000018000010
80024400438001111800001080059306407748006920800712016000018000010
80024400468001111800001080000306401488001020800002016000018000010
80024400468001111800001080000306401848001020800002016000018000010
80024400488001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010
80024400438001111800001080000306400408001020800002016000018000010