Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LDR (register, uxtw, 32-bit)

Test 1: uops

Code:

  ldr w0, [x6, w7, uxtw]
  mov x7, #4
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
10056471021110201000816610001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000
10045431001110001000804010001000200011000

Test 2: Latency 1->2 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, w7, uxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x6, x6, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0042

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570551401083010710001301301000318597286939754010630210100046022020008300031000030100
4020470052401033010310000301031001518597376941084015030247100176022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020470065401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470040401023010210000301031000318593926939934010630212100046022420008300021000030100
4020570138401103010810002301351000318593926939934010630212100046022420008300021000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0047

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570157400183001710001300401000018596586936744001030020100006002020000300031000030010
4002470049400133001310000300101000018595176946644001030020100006012220034300081000030010
4002470049400133001310000300101000018595176946644001030020100006012220036300091000030010
4002470049400133001310000300101000018597876947674001030020100006002020000300021000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300021000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300021000030010
4002470044400123001210000300101000018595446946754001030020100006002020000300031000030010
4002570072400203001810002300451000418604277299614001730032100056002020000300031000030010
4002470042400123001210000300101000018595176946644001030020100006002020000300031000030010
4002470042400123001210000300101000018597066947344001030020100006002020000300031000030010

Test 3: Latency 1->3 (with chain penalty)

Chain cycles: 3

Code:

  ldr w0, [x6, w7, uxtw]
  eor x8, x8, x0
  eor x8, x8, x0
  add x7, x7, x8
  mov x7, #4
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4020570154401083010710001301301000318593446938514010630210100046022420008300021000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300021000030100
4020470047401033010310000301031000318620386950644010630212100046022420008300031000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300031000030100
4020470047401033010310000301031000318593926939934010630212100046022420008300031000030100
4020470040401023010210000301031000318595816940634010630212100046022420008300031000030100
4020470043401023010210000301031000318595816940634010630212100046022420008300031000030100
4020470078401043010410000301031000318614566946774010630210100046022420008300031000030100
4020470056401023010210000301031000318597976941474010630212100046022420008300021000030100
4020470049401033010310000301031000318596356940834010630212100046022420008300031000030100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 3 chain cycles): 4.0049

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
4002570156400183001710001300401000318596776937164001630030100046002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002570079400213001910002300451000018601656949214001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010
4002470049400133001310000300101000018597066947344001030020100006002020000300031000030010

Test 4: throughput

Count: 8

Code:

  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  ldr w0, [x6, w7, uxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205402058013310180032100800083002561908010820080012200160024180000100
80204400538010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80205400988013810180037100800103006400828011020080014200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100
80204400458010110180000100800083006400708010820080012200160024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80025402458004111800301080008304001908001820800122016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306424168001020800002016000018000010
80024400878001111800001080000306404188001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010
80024400508001111800001080000306401668001020800002016000018000010