Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

LSL (register, 64-bit)

Test 1: uops

Code:

  lsl x0, x0, x1
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000
100410301001100100100002560310001000200010011000

Test 2: Latency 1->2

Code:

  lsl x0, x0, x1
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101001010802594331010710214202281000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100
10204100301010110101001010702595391010710212202241000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
1002410030100211002110029025962800100281003600200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010
1002410030100211002110020025959100100201002000200201001110010

Test 3: Latency 1->3

Code:

  lsl x0, x1, x0
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101082593381010810214202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100
10204100301010110101101072595391010710212202241000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024100301002110021100282595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010
10024100301002110021100202595911002010020200201001110010

Test 4: throughput

Count: 8

Code:

  lsl x0, x8, x9
  lsl x1, x8, x9
  lsl x2, x8, x9
  lsl x3, x8, x9
  lsl x4, x8, x9
  lsl x5, x8, x9
  lsl x6, x8, x9
  lsl x7, x8, x9
  mov x8, 9
  mov x9, 10

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.3342

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
802042695580115801158012024036080120802221602428001480100
802042675480115801158012024036080120802241602488001580100
802042675880115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241603488005880100
802042673780115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241602488001580100
802042673780115801158012024036080120802241602488001580100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.3339

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
800242805380037800378004226147780042800461600208001180010
800242677380021800218002028273880020800201600208001180010
800242672180021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010
800242671780021800218002028273880020800201600208001180010