Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

MOVK (32-bit)

Test 1: uops

Code:

  movk w0, #0x1234, lsl 16
  mov x0, 1

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000
100410301001100110002560310001000100010011000

Test 2: Latency 1->1

Code:

  movk w0, #0x1234, lsl 16
  mov x0, 1

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101082593291010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100
10204100301010110101101072595391010710212102121000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024100301002110021100282595291003010036100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010
10024100301002110021100202595911002010020100201001110010

Test 3: throughput

Count: 8

Code:

  movk w0, #0x1234, lsl 16
  movk w1, #0x1234, lsl 16
  movk w2, #0x1234, lsl 16
  movk w3, #0x1234, lsl 16
  movk w4, #0x1234, lsl 16
  movk w5, #0x1234, lsl 16
  movk w6, #0x1234, lsl 16
  movk w7, #0x1234, lsl 16

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.3342

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80204268838011580115801202403608012080222802228001580100
80204267428011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802238001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100
80204267378011580115801202403608012080224802248001580100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.3339

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80024280188003780037800422614828004380046800468002780010
80024267768002180021800202774048002080020800208001180010
80024267138002180021800202605898009880104800208001180010
80024267168002180021800202774048002080020800208001180010
80024267178002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010
80024267138002180021800202774048002080020800208001180010