Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

SMULH

Test 1: uops

Code:

  smulh x0, x0, x1
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000
100430301001100110002585610001000200010011000

Test 2: Latency 1->2

Code:

  smulh x0, x0, x1
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 3.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204300301010110101101002601441010010206202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 3.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024300301002110021100202599161002010028200201001110010
10024300301002110021100202599161002010020200201001110010
10024300301002110021100202599161002010020200201001110010
10024300301002110021100202599161002010020200201001110010
10025300601002610026100342599161002010020200361001110010
10024300301002110021100202599161002010020200201001110010
10024300301002110021100202599161002010020200201001110010
10024300301002110021100202599161002010020200201001110010
10024302031004910049100802599161002010020200201001110010
10024300301002110021100202599161002010020200201001110010

Test 3: Latency 1->3

Code:

  smulh x0, x1, x0
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 3.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204300301010110101101002601501010010206202121000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10205300601010610106101142601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100
10204300301010110101101002601561010010208202161000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 3.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020026001900100341004800200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010
1002430030100211002110020025991600100201002000200201001110010

Test 4: throughput

Count: 8

Code:

  smulh x0, x8, x9
  smulh x1, x8, x9
  smulh x2, x8, x9
  smulh x3, x8, x9
  smulh x4, x8, x9
  smulh x5, x8, x9
  smulh x6, x8, x9
  smulh x7, x8, x9
  mov x8, 9
  mov x9, 10

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0004

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
802048005480104801048010524036980124802371602248000480100
802048003480104801048010524031580105802121602248000480100
802048003480104801048010524031580105802121602728002080100
802048003480104801048010524031580105802121602248000480100
802048003480104801048010524031580105802121602248000480100
802048003480104801048010524031580105802121602248000480100
802048003480104801048010524036980124802361602248000480100
802058006680120801208012424031580105802121602248000480100
802048003480104801048010524031580105802121602248000480100
802048003480104801048010524031580105802121602248000480100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0004

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
800248003580025800258002624006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024013280045800561600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024006080020800201600208001180010
800248003280021800218002024013280045800601600208001180010