Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

ST1 (single, post-index, B)

Test 1: uops

Code:

  st1 { v0.b }[1], [x6], x8
  nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop ; nop
  mov x0, 0
  mov x8, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires (minus 60 nops): 2.000

Issues: 3.000

Integer unit issues: 1.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 1.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map ldst uop (7d)map simd uop (7e)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)
6200629601300710031002100210021002100030008751400030001000100030001000100110001000
6200429420300110011000100010001000100030008751400030001000100030001000100110001000
6200429407300110011000100010001000100030008751400030001000100030001000100110001000
6200429407300110011000100010001000100030008751400030001000100030001000100110001000
6200429419300110011000100010001000100030008751400030001000100030001000100110001000
6200429423300110011000100010001000100030008751400030001000100030001000100110001000
6200429578300110011000100010001000100030008751400030001000100030001000100110001000
6200429592300110011000100010001000100030008751400030001000100030001000100110001000
6200429407300110011000100010001000100030008751400030001000100030001000100110001000
6200429426300110011000100010001000100030008751400030001000100030001000100110001000

Test 2: throughput

Count: 8

Code:

  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  st1 { v0.b }[1], [x6], x8
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6
  mov x8, 0

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
1602068014624018680131800378001880139800398000412234311359954320038240122200800098000920024001880006800018000080000100
160204800452401088010180007800008010980009800026804361360058320026240114200800068000620024001880006800058000080000100
160205801082401858013180036800188013880038800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160204800452401058010180004800008010680006800026804361360058320026240114200800068000620024001880006800018000080000100
160205801042401858013180036800188013880038800024208551360184320026240114200800068000620024001880006800018000080000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
1600268014524009380041800348001880046800368003314134291360361320150240117208003780037202400248000880002800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
1600248004524001180011800008000080010800008003215952951360649320146240114208003680036202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010
160024800452400118001180000800008001080000800006801591360052320000240010208000080000202400008000080001800008000010