Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (D)

Test 1: uops

Code:

  str d0, [x6]
  mov x0, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115610191101810001707910001000200011000
1004104710011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004104710011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001693710001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000

Test 2: throughput

Count: 8

Code:

  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  str d0, [x6]
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80204800688010110180000100800013001359992080101200800080200160016180000100
80204800478010110180000100800013001359886080101200800080200160016180000100
80204800398010110180000100800013001359886080101200800080200160016180000100
80204800398010110180000100800013001359886080101200800080200160016180000100
80204800398010110180000100800013001359886080101200800080200160016180000100
80204800398010110180000100800013001359886080101200800080200160016180000100
80205800678011810180017100800013001359886080101200800080200160016180000100
952481162009715098068734410722800013001359886080101200800080200160016180000100
80204800468010110180000100800763001362193080176200800930200160016180000100
80204802378013710180036100800013001360012080101200800080200160016180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258014780029118001810800373013602948004720800522016001618000010
800248003780011118000010800003013598478001020800002016000018000010
800248003880011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016018418000010
800248006780011118000010800003013600078001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010