Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (Q)

Test 1: uops

Code:

  str q0, [x6]
  mov x0, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005134010191101810001704310001000200011000
1004104710011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004104010011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004104010011100010001688310001000200011000

Test 2: throughput

Count: 8

Code:

  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  str q0, [x6]
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
802058015480119101800181008000130013599380801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048005580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001600161800000100
802048004580101101800001008000130013600100801012008000802001601041800000100
802048004580101101800001008000130013600100801012008000802001600161800000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258015180029118001810800003013599718001020800002016000018000010
800258007380028118001710800003013599718001020800002016000018000010
800248004580011118000010800003013600078001020800002016000018000010
800248004580011118000010800003013600078001020800002016000018000010
800248004580011118000010800003013600258001020800002016010418000010
800248004580011118000010800003013600438001020800002016000018000010
800248004580011118000010800003013600078001020800002016000018000010
800248004580011118000010800363013601278004620800512016000018000010
800248004580011118000010800373013606888004720800522016000018000010
800248004580011118000010800003013600078001020800002016000018000010