Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, D)

Test 1: uops

Code:

  str d0, [x6, x7]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115610191101810001704310001000300011000
1004104710011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001704310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000

Test 2: throughput

Count: 8

Code:

  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  str d0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
80205801558011910180018100800013001359902801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100
80204800378010110180000100800013001359850801012008000820024002401800000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258014880029118001810800003013598658001020800002024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248003780011118000010800343013599518004420800492024000018000010
800248003780011118000010800003013598838001020800002024000018000010
800248542380047118003610800003013598478001020800002024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248003780011118000010800003013598658001020800002024000018000010
800248003780011118000010800363013609278004620800412024000018000010
800248003780011118000010800003013598478001020800002024012318000010