Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, S)

Test 1: uops

Code:

  str s0, [x6, x7]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115310191101810001700710001000300011000
1004103710011100010001684710001000300011000
1004104510011100010001684710001000300011000
1004103710011100010001684710001000300011000
1004103710011100010001684710001000300011000
1004103710011100010001684710001000300011000
1004103710011100010001684710001000300011000
1004103810011100010001684710001000300011000
1004103710011100010001686510001000300011000
1004103910011100010001684710001000300011000

Test 2: throughput

Count: 8

Code:

  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  str s0, [x6, x7]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
8020580156801191018001810080001300135977808010120080008020024002401800000100
8020480037801011018000010080001300135985008010120080008020024002401800000100
8020480045801011018000010080001300136001008010120080008020024002401800000100
8020480045801011018000010080001300136001008010120080008020024002401800000100
8020480039801011018000010080001300135988608010120080008020024002401800000100
8020480039801011018000010080001300135988608010120080008020024002401800000100
8020480039801011018000010080001300135988608010120080008020024002401800000100
8020480039801011018000010080034300135998708013420080049020024002401800000100
8020480135801191018001810080001300135988608010120080008020024002401800000100
8020480039801011018000010080001300136010008010120080008071483654324280812218073053

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258015380029118001810800013013600468001120800082024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004980011118000010800003013600438001020800002024000018000010
800248005380011118000010800003013600438001020800002024003018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010