Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, lsl, 32-bit)

Test 1: uops

Code:

  str w0, [x6, x7, lsl #2]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115610191101810001704310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000

Test 2: throughput

Count: 8

Code:

  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  str w0, [x6, x7, lsl #2]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
802058015080119101800181008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802058007480118101800171008000130013599048010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100
802048003980101101800001008000130013598868010120080008200240024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
80025801518002911800181080000301359811800102080000202400000180000010
80024800458001111800001080000301359847800102080000202400000180000010
80025800658002811800171080000301359798800102080000202400000180000010
80024800378001111800001080000301359847800102080000202401560180000010
80024800378001111800001080000301359847800102080000202400000180000010
80024800378001111800001080000301359847800102080000202400000180000010
80024800378001111800001080000301359847800102080000202400000180000010
80024800378001111800001080000301359847800102080000202400000180000010
80024800378001111800001080000301359847800102080000202400000180000010
80024800378001111800001080000301359847800102080000202400000180000010