Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, lsl, D)

Test 1: uops

Code:

  str d0, [x6, x7, lsl #3]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115010191101810001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000
1004104710011100010001704310001000300011000

Test 2: throughput

Count: 8

Code:

  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  str d0, [x6, x7, lsl #3]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
80205801478011910108001810008000130013599748010120080008200240024180000100
916771139419020862502108374858872038000130013601728010120080008200240156180000100
80204800478010110108000010008000130013600468010120080008200240024180000100
80204800478010110108000010008000130013600468010120080008200240024180000100
80204800478010110108000010008000130013600468010120080008200240156180000100
80204800888010110108000010008000130013600468010120080008200240024180000100
80204802398013710108003610008000130013600828010120080008200240024180000100
80204800478010110108000010008000130013600468010120080008200240024180000100
80204800478010110108000010008003730013601688013720080052200240024180000100
80204800478010110108000010008000130013600468010120080008200240024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258015480029118001810800013013599748001120800082024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800258007380028118001710800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800248004580011118000010800003013600078001020800002024000018000010
800258007380028118001710800003013600258001020800002024002418000010
800248014380029118001810801083013633018011820801232024000018000010
800248004780011118000010800003013600438001020800002024000018000010