Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, sxtw, Q)

Test 1: uops

Code:

  str q0, [x6, w7, sxtw]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005149410191101810001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000

Test 2: throughput

Count: 8

Code:

  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  str q0, [x6, w7, sxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
8020580377801191010800181000800013001359974080101200800080200240024180000100
8020580073801181010800171000800013001359778080101200800080200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100
8020480037801011010800001000800373001360134080137200800520200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100
8020580066801181010800171000800013001359868080101200800080200240024180000100
8020480037801011010800001000800013001359850080101200800080200240024180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258051380029118001810800013013600108001120800082024000018000010
800248003980011118000010800343013601498004420800492024000018000010
800248003980011118000010800003013598838001020800002024000018000010
800258006780028118001710800003013598838001020800002024000018000010
800248003980011118000010800343013600058004420800492024000018000010
800248003980011118000010800013013603228001120800082024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248003780011118000010800003013598478001020800002024000018000010
800248004280011118000010800003013599738001020800002024000018000010