Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, uxtw, 32-bit)

Test 1: uops

Code:

  str w0, [x6, w7, uxtw]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005114810191101810001707910001000300011000
1004104210011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004104710011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001688310001000300011000
1004103910011100010001695510001000300011000
1004103910011100010001690110001000300011000
1004104010011100010001688310001000300011000

Test 2: throughput

Count: 8

Code:

  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  str w0, [x6, w7, uxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
8020580153801191018001810080001300135993880101200800082002400241800000100
8020480045801011018000010080001300135985080101200800082002400241800000100
8020480037801011018000010080001300135985080101200800082002401561800000100
8020480037801011018000010080001300135985080101200800082002400241800000100
8020480037801011018000010080001300135995880101200800082002400241800000100
8020480037801011018000010080001300135988680101200800082002400241800000100
8020480037801011018000010080001300135985080101200800082002400241800000100
8020480037801011018000010080001300135985080101200800082002400241800000100
8020480037801011018000010080001300135985080101200800082002400241800000100
8020480038801011018000010080001300135985080101200800082002401471800000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258015680029118001810800363013601278004620800512024002418000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010
800248004780011118000010800363013601278004620800512024000018000010
800248004780011118000010800003013602418001020800002024000018000010
800248004780011118000010800003013600438001020800002024000018000010