Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (register, uxtw, Q)

Test 1: uops

Code:

  str q0, [x6, w7, uxtw]
  mov x0, 0
  mov x7, 8

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005115310191101810001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000
1004104510011100010001700710001000300011000

Test 2: throughput

Count: 8

Code:

  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  str q0, [x6, w7, uxtw]
  mov x7, 8

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0006

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
802058014880119101800181008000130013599748010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048004580101101800001008003630013601278013620080051200240024180000100
802048004580101101800001008000130013600108010120080008200240024180000100
802048049180137101800361008014530013695688024520080172200240768180000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800258015180029118001810800003013598658001020800002024000018000010
800248003980011118000010800003013598838001020800002024000018000010
800248003980011118000010800003013595698001020800002024000018000010
800248004380011118000010800003013599018001020800002024000018000010
800258008080028118001710800003013592738001020800002024000018000010
800248003980011118000010800363013609638004620800412024003018000010
800268017280045118003410800013013598868001120800082024000018000010
800248003980011118000010800003013598838001020800002024015618000010
800248003980011118000010800003013598838001020800002024000018000010
800248003980011118000010800003013598838001020800002024000018000010