Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

STR (signed offset, D)

Test 1: uops

Code:

  str d0, [x6, #0x10]
  mov x0, 0

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 0.001

Load/store unit issues: 1.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch ldst uop (58)simd uops in schedulers (5a)dispatch uop (78)map ldst uop (7d)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)
1005114910191101810001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000
1004103910011100010001688310001000200011000

Test 2: throughput

Count: 8

Code:

  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  str d0, [x6, #0x10]
  mov x7, x6
  mov x8, x6
  mov x9, x6
  mov x10, x6
  mov x11, x6
  mov x12, x6
  mov x13, x6

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule simd uop (54)schedule ldst uop (55)dispatch int uop (56)dispatch simd uop (57)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)ldst uops in schedulers (5b)dispatch uop (78)map int uop (7c)map ldst uop (7d)map simd uop (7e)map int uop inputs (7f)map ldst uop inputs (80)map simd uop inputs (81)? int output thing (e9)? ldst retires (ed)? simd retires (ee)? int retires (ef)
802058015180119101080018100080001300135981408010120080008020016001601800000100
802048003980101101080000100080001300135988608010120080008020016001601800000100
802048003980101101080000100080001300135988608010120080008020016001601800000100
802048003980101101080000100080001300135988608010120080008020016010401800000100
802048004780101101080000100080001300135988608010120080008020016001601800000100
802048003980101101080000100080001300135988608010120080008020016010401800000100
802048004780101101080000100080037307136000808013920280050020016010201800000100
802048003980101101080000100080001300135988608010120080008020016001601800000100
802058006880118101080017100080001300135988608010120080008020016001601800000100
802048003980101101080000100080001300135988608010120080008020016001601800000100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 1.0005

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)schedule ldst uop (55)dispatch int uop (56)dispatch ldst uop (58)int uops in schedulers (59)simd uops in schedulers (5a)dispatch uop (78)map int uop (7c)map ldst uop (7d)map int uop inputs (7f)map ldst uop inputs (80)? int output thing (e9)? ldst retires (ed)? int retires (ef)
800268030580046118003510800013013600108001120800082016001618000010
800248004580011118000010800003013598478001020800002016000018000010
800248005580011118000010800003013599918001020800002016000018000010
800248003780011118000010800013013600468001120800082016002018000010
800248003780011118000010800013013598508001120800082016001618000010
800248003780011118000010800013013598508001120800082016001618000010
800248003780011118000010800013013598508001120800082016001618000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010
800248003780011118000010800003013598478001020800002016000018000010