Apple Microarchitecture Research by Dougall Johnson

M1/A14 P-core (Firestorm): Overview | Base Instructions | SIMD and FP Instructions
M1/A14 E-core (Icestorm):  Overview | Base Instructions | SIMD and FP Instructions

SUBS (shifted immediate, 64-bit)

Test 1: uops

Code:

  subs x0, x0, #3, lsl #12
  mov x0, 1
  mov x1, 2

(no loop instructions)

1000 unrolls and 1 iteration

Retires: 1.000

Issues: 1.000

Integer unit issues: 1.001

Load/store unit issues: 0.000

SIMD/FP unit issues: 0.000

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000
100410301001100110002504310001000100010011000

Test 2: Latency 1->2

Code:

  subs x0, x0, #3, lsl #12
  mov x0, 1
  mov x1, 2

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10204100301010110101101082515201010610206102101000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100
10204100301010110101101082517741010810208102081000110100

1000 unrolls and 10 iterations

Result (median cycles for code): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
10024100301002110021100302532561002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010
10024100301002110021100202531611002010020100201001110010

Test 3: Latency 3->2

Chain cycles: 1

Code:

  subs x0, x1, #3, lsl #12
  cset x1, cc
  mov x0, 1
  mov x1, 2
  mov x2, 3
  mov x3, 4
  mov x4, 5

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code, minus 1 chain cycle): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
20205200602011520115201485194352010720212202142000120100
20204202292018520185202845195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204201302014520145201975195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100
20204200302010120101201085195482010820216202162000120100

1000 unrolls and 10 iterations

Result (median cycles for code, minus 1 chain cycle): 1.0030

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
20024200302001120011200185196382001820036200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010
20024200302001120011200105195982001020020200202000120010

Test 4: throughput

Count: 8

Code:

  subs x0, x8, #3, lsl #12
  subs x1, x8, #3, lsl #12
  subs x2, x8, #3, lsl #12
  subs x3, x8, #3, lsl #12
  subs x4, x8, #3, lsl #12
  subs x5, x8, #3, lsl #12
  subs x6, x8, #3, lsl #12
  subs x7, x8, #3, lsl #12
  mov x8, 9
  mov x9, 10
  mov x10, 11

(fused SUBS/B.cc loop)

100 unrolls and 100 iterations

Result (median cycles for code divided by count): 0.5010

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80204400838011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152404408014780248802168001280100
80204400818011280112801152403458011580216802488004080100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100
80204400818011280112801152403458011580216802168001280100

1000 unrolls and 10 iterations

Result (median cycles for code divided by count): 0.5004

retire uop (01)cycle (02)schedule uop (52)schedule int uop (53)dispatch int uop (56)int uops in schedulers (59)dispatch uop (78)map int uop (7c)map int uop inputs (7f)? int output thing (e9)? int retires (ef)
80024400918003280032800352400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010
80024400308002180021800202400658002080020800208001180010